sin (theta) = [13* sin (32o)]/8
= 13*0.529919264/8
= 0.861118804
[theta] = sin-1 (0.861118804)
[theta] = 59.44o
If sine theta is 0.28, then theta is 16.26 degrees. Cosine 2 theta, then, is 0.8432
degrees = pi/180 180 degrees = pi .33pi = .33 times 180 = 60 degrees
I'm asuming you meant "ten theta"the square of 5 is 2525 divided by 10 is 2.5so theta equals 2.5there you go =)
Using x instead of theta, cos2x/cosec2x + cos4x = cos2x*sin2x + cos4x = cos2x*(sin2x + cos2x) = cos2x*1 = cos2x
Yes. (Theta in radians, and then approximately, not exactly.)
If sine theta is 0.28, then theta is 16.26 degrees. Cosine 2 theta, then, is 0.8432
sin(theta) = 15/17, cosec(theta) = 17/15 cos(theta) = -8/17, sec(theta) = -17/8 cotan(theta) = -8/15 theta = 2.0608 radians.
It depends if 1 plus tan theta is divided or multiplied by 1 minus tan theta.
degrees = pi/180 180 degrees = pi .33pi = .33 times 180 = 60 degrees
I'm asuming you meant "ten theta"the square of 5 is 2525 divided by 10 is 2.5so theta equals 2.5there you go =)
Sin(X) = 0.9 X = Sin^(-1) 0.9 X = 64.158... degrees.
Using x instead of theta, cos2x/cosec2x + cos4x = cos2x*sin2x + cos4x = cos2x*(sin2x + cos2x) = cos2x*1 = cos2x
It is a simple trigonometric equation. However, without information on whether the angles are measures in degrees or radians, and with no domain for theta, the equation cannot be solved.
Yes. (Theta in radians, and then approximately, not exactly.)
cos(theta) = 0.7902 arcos(0.7902) = theta = 38 degrees you find complimentary angles
theta = arcsin(0.0138) is the principal value.
The answer is 60 and 240 degrees. Add radical 3 and inverse tan to get answer add 180 for other answer less than 360.