It depends if 1 plus tan theta is divided or multiplied by 1 minus tan theta.
- cos theta
sin(theta) = 15/17, cosec(theta) = 17/15 cos(theta) = -8/17, sec(theta) = -17/8 cotan(theta) = -8/15 theta = 2.0608 radians.
Tan^2
Since sin(theta) = 1/cosec(theta) the first two terms simply camcel out and you are left with 1 divided by tan(theta), which is cot(theta).
By converting cosecants and secants to the equivalent sine and cosine functions. For example, csc theta is the same as 1 / sin thetha.
Using x instead of theta, cos2x/cosec2x + cos4x = cos2x*sin2x + cos4x = cos2x*(sin2x + cos2x) = cos2x*1 = cos2x
It also equals 13 12.
It is 1.
I'm asuming you meant "ten theta"the square of 5 is 2525 divided by 10 is 2.5so theta equals 2.5there you go =)
Zero. Anything minus itself is zero.
- cos theta
cosine (90- theta) = sine (theta)
-2(cot2theta)
Yes. (Theta in radians, and then approximately, not exactly.)
sin(theta) = 15/17, cosec(theta) = 17/15 cos(theta) = -8/17, sec(theta) = -17/8 cotan(theta) = -8/15 theta = 2.0608 radians.
theta = arcsin(0.0138) is the principal value.
sin (theta) = [13* sin (32o)]/8 = 13*0.529919264/8 = 0.861118804 [theta] = sin-1 (0.861118804) [theta] = 59.44o