you are able to answer your question by using the following formula of estimating crude protein content in food or whatever protein percent you would like to estimate.
protein percentage =
(titration value- blank titration value )(0.01*14.007)
weight of sample used
Multiply the result by 100 and afterwards by 6.25 factor.
then you will get the accurate protein percentage that you are looking for .
hope that helped out .
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They are the percentage of protein in the horse feed.
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70% alcohol has been found to be more effective in killing microbes.Higher and lower concentration may not be as effective.90% alcohol coagulate proteins in contact.suppose 90% alcohol is poured over one celled organism,the alcohol penetrate the cellwall of the organism.the coagulated protein would then prevent the alcohol further from the cell and no more coagulation then take place.now,if 70% alcohol is added into one celled organism.The diluted alcohol also coagulates the protein, but at a slower rate,so that it penetrates all the cell before coagulation.Then all the cell coagulated and the organism died.
Let S be the amount in pounds of soyabean meal and C be the amount in pounds of cornmeal.You can create two equations relating S & C by considering the amount of protein and total weight:16% S + 8% C = 14% of 320 lbS + C = 320 lbwhich can be used together to solve for S and C:subtract 6¼ times {1} from {2} to get:S - 16%S × 6¼ + C - 8% C × 6¼ = 320 - 14 × 6¼ of 320→ 100% S - 100% S + 100% C - 50% C = 100% of 320 - 87½% of 320→ 50% C = 12½% of 320→ C = 25% of 320 = 80Now substitute for C in {2}:S + 80 = 320→ S = 240Therefore you need 240lb of soyabean meal and 80 lb of cornmeal.
If you deduct 2.50 from 2.80 you find there has been a 0.30 increase. If you then divide 0.30 by the original amount of 2.50 and multiply the resulting answer by 100 (to get it in %) you will find that this corresponds to an increase of 12%.