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How do you take a number to a frational power?
The easiest way to do this is with a calculator. Anyway, the definitions are as follows. x to the power 1/2 is the square root of x, x to the power 1/3 is the cubic root of x, and in general, x to the power 1/n is the nth. root of x. If you also have a number other than one in the numerator: For example, to calculate x to the power 3/5 you first raise x to the power 3, then take the fifth root of the result. You can also do it the other way: first calculate the fifth root, then raise to the third power. In general, to calculate x to the power m/n, you take the nth root, then raise the result to the power m.
What is the nth root of 244?
The nth root of a number is that number which when raised to the nth power (ie when multiplied by itself n times) results in the number. When n=2, it is the square root of the number; when n=3 it is the cube root of the number. To find the nth root of a number, an electronic calculator can be used, using the nth root button [x√y] (though more recent calculators replace the x and y by boxes) viz: <n> [x√y] [2] [4] [4] [=] or with the more recent calculators: [#√#] <n> [Navigate →] [2] [4] [4] [=] where <n> is the nth root, eg for 2nd root (square roots) enter [2]; and the # is being used to represent a box on the keys of the more recent calculator. Considering the rules for indices, the nth root is the the number to the power of 1/n, ie 244^(1/n), thus the calculation can be done using the power button: [2] [4] [4] [^] [(] [1] [÷] <n> [)] [=] With the more recent calculators, the power button is pressed first, the 244 entered, the navigate-right key pressed (to get in to the power part of the input) and then the n entered.
How do you calculate the nth term in the Fibonacci sequence using C?
what? Assuming you wanted an algorithm to find the nth number in the Fibonacci sequence: double Fib(int i) { double x = 1; double y = 1; if (i
What is the Nth term for a triangle number?
The Nth term for a triangle number is: 0.5n(n+1)
How can you find the nth square number?
Three ways.. Multiply n by itself. Calculate Sum[2i+1,{i,0,n-1}] Calculate Sum[n,{i,1,n}]
