The lengths of the diagonals work out as 12 cm and 16 cm
The edge lengths are: 7 cm
Convert to the same units then you can do the division: 1 ft = 30.48 cm (exactly) → 35 ft ÷ 60 cm = 35 × 30.48 cm ÷ 60 cm = 1066.8 ÷ 60 = 17.78 You can get 17 whole lengths of 60 cm and 0.78 of a 60 cm length (or 17 whole lengths of 60 cm and 46.8 cm left over)
547 cm or 5.47 m
Using Pythagoras' theorem and the quadratic equation formula they work out as 9.9 cm and 13.2 cm in lengths. Check: 9,9+13.2+16.5 = 39.6 cm which is its perimeter
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The lengths of the diagonals work out as 12 cm and 16 cm
1m = 100 cm so 3m = 300 cm300 cm/60 cm = 5 lengths.
7cm
If you are given two lengths with the units of centimeters just multiply the two cm lengths and you have cmxcm which is cm2
32 cm
The edge lengths are: 7 cm
Convert to the same units then you can do the division: 1 ft = 30.48 cm (exactly) → 35 ft ÷ 60 cm = 35 × 30.48 cm ÷ 60 cm = 1066.8 ÷ 60 = 17.78 You can get 17 whole lengths of 60 cm and 0.78 of a 60 cm length (or 17 whole lengths of 60 cm and 46.8 cm left over)
There are 50.
The partner lengths for a line segment 8 cm long are 1cm + 7cm, 2cm + 6cm, 3cm + 5 cm, and 4 cm + 4cm
It is 2.39 metres or 239 cm.
547 cm or 5.47 m