The lengths of the diagonals work out as 12 cm and 16 cm
The edge lengths are: 7 cm
Convert to the same units then you can do the division: 1 ft = 30.48 cm (exactly) → 35 ft ÷ 60 cm = 35 × 30.48 cm ÷ 60 cm = 1066.8 ÷ 60 = 17.78 You can get 17 whole lengths of 60 cm and 0.78 of a 60 cm length (or 17 whole lengths of 60 cm and 46.8 cm left over)
547 cm or 5.47 m
Using Pythagoras' theorem and the quadratic equation formula they work out as 9.9 cm and 13.2 cm in lengths. Check: 9,9+13.2+16.5 = 39.6 cm which is its perimeter
yes
The lengths of the diagonals work out as 12 cm and 16 cm
1m = 100 cm so 3m = 300 cm300 cm/60 cm = 5 lengths.
7
If you are given two lengths with the units of centimeters just multiply the two cm lengths and you have cmxcm which is cm2
32 cm
The edge lengths are: 7 cm
Convert to the same units then you can do the division: 1 ft = 30.48 cm (exactly) → 35 ft ÷ 60 cm = 35 × 30.48 cm ÷ 60 cm = 1066.8 ÷ 60 = 17.78 You can get 17 whole lengths of 60 cm and 0.78 of a 60 cm length (or 17 whole lengths of 60 cm and 46.8 cm left over)
The partner lengths for a line segment 8 cm long are 1cm + 7cm, 2cm + 6cm, 3cm + 5 cm, and 4 cm + 4cm
It is 2.39 metres or 239 cm.
547 cm or 5.47 m
Using Pythagoras' theorem and the quadratic equation formula they work out as 9.9 cm and 13.2 cm in lengths. Check: 9,9+13.2+16.5 = 39.6 cm which is its perimeter