Suppose length is L cm. Then Width = L-15 cm Perimeter = 2*(W+L) = 2*(L-15 + L) = 2*(2L - 15) = 4L - 30 cm So 4L - 30 = 98 so that 4L = 128 and then L = 32 cm Then W = L - 15 = 32- 15 = 17 cm. So the rectangle is 32 cm * 17 cm
-3.5
Suppose the length is L cm. Then the width, W, is 2L/3 cm. Perimeter = 2(L+W) = 2(L+2L/3) = 10L/3 = 90 cm So L = 27 cm and W = 2L/3 = 18 cm.
There is no conversion of cm to l .But , cubic cm and litre has relation. so,1 cc=0.001 l.
L is a measure of volume, while cm is a measure of distance. A cubic centimeter, written both as cc and cm^3, is a measure of volume, and 1 cc = 1 mL = 0.001 L
Any number greater than or equal to 4*sqrt(45) cm or 26.83 cm (approx). To see that, suppose L ≥ sqrt(45) cm be the length of the rectangle and let B = 45/L cm Then Area = L*B = L*(45/L) = 45 cm2 If L = 9cm, then B = 45/9 = 5 cm and then perimeter = 2*(L+B) = 28 cm If L = 90 cm, then B = 0.5 cm and P = 181 cm If L = 900 cm, then B = 0.05 cm and P = 1800.1 cm If L = 9000000 cm then B = 0.000005 cm and P = 18000000.00001 cm As can be seen, the perimeter can be increased without limit.
If 150 / x = 66, then x = 2.2727 cmSuppose the length is L cm.Then 150*L cm = 66 cmSo L cm = 66 cm/150 = 66/150 cm = 0.44 cm = 4.4 mm.
1 L = 1000 mL = 1000 cm cubed
Suppose length is L cm. Then Width = L-15 cm Perimeter = 2*(W+L) = 2*(L-15 + L) = 2*(2L - 15) = 4L - 30 cm So 4L - 30 = 98 so that 4L = 128 and then L = 32 cm Then W = L - 15 = 32- 15 = 17 cm. So the rectangle is 32 cm * 17 cm
-3.5
Suppose the length is L cm. Then the width, W, is 2L/3 cm. Perimeter = 2(L+W) = 2(L+2L/3) = 10L/3 = 90 cm So L = 27 cm and W = 2L/3 = 18 cm.
1 l = 1000 cm³ → 0.75 l = 0.75 x 1000 cm³ = 750 cm³ (1 cm³ = 1 ml)
30=2(6)+2(l) 30=12+2(l) 18+2(l) length is 9 cm
Conversion of m to cm and mm: 1 m = 100 cm; 1 m = 1000 mmConversion of l to ml: 1 L = 1000 ml
The perimeter of a rectangle is simply the sum of the length of all four sides. So, l + w + l + w, or 2(l + w).
The perimeter of a rectangle is P = 2(l + w) where: l = length w = width Let: l = 15 cm w = 10 cm Then: P = 2(15 cm + 10 cm) = 2(25 cm) = 50 cm So the perimeter of a rectangle is 50 cm.
There are infinitely many ways. Pick any number greater than or equal to sqrt(20) = 4.472 cm. Let that be the length of your rectangular area, L. Let the breadth be B = 20/L cm. Then clearly, area = L*B = L*(20/L) = 20 cm2 So, L = 20 cm gives B = 1 cm L = 10 cm gives B = 2 cm L = 5 cm gives B = 4 cm L = 1 metre gives B = 0.2 cm L - 1 kilometre gives B = 0.0002 cm and so on. There is no need to stick with rectangles: yuo could do circles, triangles, other polygons or even irregular shapes. Cut out 20 squares of 1 cm each and arrange them so that each one of them is "connected" side-to-side with another. You can make L-shapes, and F-shapes and all sorts. Its just that rectangles are easiest to calculate and present an answer.