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How do you find the width and perimeter of a rectangle if the length is 156 cm and the width is 36 more than one half of the length?
L = 156 cm so L/2 = 156/2 = 78 cm and so width = W = 36 cm more = 78+36 = 114 cm Then perimeter = 2*(L+W) = 2*(156 + 114) cm = 2*270 cm = 540 cm
How many different rectangles can you draw with an area of 11 cm squared?
There are infinitely many rectangles. Let K = sqrt(11). Let L be any real number greater than M and let B = 11/L. Then, B < K so that for any two different values of L, the pair (L, B) are distinct even with a swap.The rectangle with length L and breadth B has an area = L*(11/L) = 11 cm2. Since there are infinitely many choices for L, there are infinitely many rectangles.
How many cm in 100 meters?
One
What are the dimensions of rectangle if the diagonal is 13cm?
The length of the diagonal is not enough to determine the dimensions of the rectangle. Take any length W such that 0<W<sqrt(132/2) that is, 0<W<9.192 cm. And let L = sqrt(132 - W2) cm. Then 9.192<L<13 so that any combination of W and L is unique. There are infinitely many possible values for W and so infinitely many different combinations for W and L. That is, infinitely many rectangles whose width is W cm and length is L cm. And, since, L2 = 132 - W2, L2 + W2 = 132 so the diagonal is 13 cm.
How many CM in one metre?
100 cm = 1 meter
