A variable defined on a continuous interval as opposed to one that can take only discrete values.
A 1-dimensional interval (a, b) is continuous if for any k in (0, 1) the point a + k*(b-a) = a*(1-k) + k*b is also in the interval. This is equivalent to the statement that every point on the line joining a and b is in the interval. The above can be extended to more dimensions analogously.
Yes, it is a Continuous variable measured along an equidistant scale.
The linear discrete time interval is used in the interpretation of continuous time and discrete valued: Quantized signal.
Yes it is because it is a measurement of something usually entering into decimal figures and cannot be simply counted.
Yes.
A variable defined on a continuous interval as opposed to one that can take only discrete values.
A 1-dimensional interval (a, b) is continuous if for any k in (0, 1) the point a + k*(b-a) = a*(1-k) + k*b is also in the interval. This is equivalent to the statement that every point on the line joining a and b is in the interval. The above can be extended to more dimensions analogously.
FXY is a n investment, like buying Japanese Yen, but traded at NYSE in US Dollars. It will go up and down in value like owning Japanese Yen would.
If the function is continuous in the interval [a,b] where f(a)*f(b) < 0 (f(x) changes sign ) , then there must be a point c in the interval a<c<b such that f(c) = 0 . In other words , continuous function f in the interval [a,b] receives all all values between f(a) and f(b)
Yes, it is a Continuous variable measured along an equidistant scale.
Yes, land area is considered an interval variable because it can be measured on a continuous scale with equal units between values.
why doesn't wiki allow punctuation??? Now prove that if the definite integral of f(x) dx is continuous on the interval [a,b] then it is integrable over [a,b]. Another answer: I suspect that the question should be: Prove that if f(x) is continuous on the interval [a,b] then the definite integral of f(x) dx over the interval [a,b] exists. The proof can be found in reasonable calculus texts. On the way you need to know that a function f(x) that is continuous on a closed interval [a,b] is uniformlycontinuous on that interval. Then you take partitions P of the interval [a,b] and look at the upper sum U[P] and lower sum L[P] of f with respect to the partition. Because the function is uniformly continuous on [a,b], you can find partitions P such that U[P] and L[P] are arbitrarily close together, and that in turn tells you that the (Riemann) integral of f over [a,b] exists. This is a somewhat advanced topic.
Yes, skin temperature in degrees centigrade is considered interval data. Interval data is continuous data that has a meaningful zero point, but ratios between values are not meaningful. Skin temperature can be measured on a continuous scale with a specific unit of measurement (degrees centigrade) where a value of zero does not indicate absence of skin temperature.
The airport code for Forest City Municipal Airport is FXY.
sorry but are gone mad
Interval training is periods of work followed by periods of rest. This is known as work:rest ratio. This is commonly used to train the anaerobic energy system. Continuous training, of which there are many forms does not involve rest periods, although it could involve periods of different intensities (such as Fartlek training).