It is the number x such that 10^x = 2.
It is approx 0.3010
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The antilogarithm (or antilog) of a number is found by raising 10 to that number if it's a common logarithm (base 10). Therefore, the antilog of 4.33206 is calculated as (10^{4.33206}), which equals approximately 21,436.49.
If a number has an antilog whose integer part is n, then the number has n-1 digits before the decimal point.
The answer is easy if you are familiar with scientific notation. The antilog of a number, whose integer part is n, has 10n in its scientific notation. Otherwise: the number that you want the antilog for will normally be in decimal form: consisting of an integer part, a decimal point and a fractional part. The number of integer digits in the antilog is one more than the integer part of the number being "antilogged" (exponentiated). antilog(0.1234) = 1.3286*100 = 1.3286 antilog(1.1234) = 1.3286*101 = 13.286 antilog(5.1234) = 1.3286*105 = 132860 antilog(-3.1234) = 1.3286*10-3 = 0.0013286
1.Using calculator-press the 'shift' button and then the log number to be converted. N:B:Estimate answer to 3 s.f 2.You can also fin antilog by raising the log by power 10.e.g antilog of x is 10^x
The antilog of -4.45 refers to the inverse operation of taking the logarithm base 10 of a number. To find the antilog of -4.45, you would raise 10 to the power of -4.45. This can be calculated as 10^(-4.45), which equals approximately 3.54813389234.