If a number has an antilog whose integer part is n, then the number has n-1 digits before the decimal point.
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The answer is easy if you are familiar with scientific notation. The antilog of a number, whose integer part is n, has 10n in its scientific notation. Otherwise: the number that you want the antilog for will normally be in decimal form: consisting of an integer part, a decimal point and a fractional part. The number of integer digits in the antilog is one more than the integer part of the number being "antilogged" (exponentiated). antilog(0.1234) = 1.3286*100 = 1.3286 antilog(1.1234) = 1.3286*101 = 13.286 antilog(5.1234) = 1.3286*105 = 132860 antilog(-3.1234) = 1.3286*10-3 = 0.0013286
To find the antilog of 0.0259, you can use the formula (10^{x}), where (x) is the value for which you want to find the antilog. In this case, calculate (10^{0.0259}). Using a calculator, you will find that the antilog of 0.0259 is approximately 1.058.
Because it is a point that is used in the decimal system of counting. Decimal means based on ten.
100 is a number, not a decimal point.
'point' or 'and' because decimal ''point''