64
Since you can calculate this in any scientific calculator (or in Excel, typing: = 2^64), it really doesn't make sense to ask that here.
Convert each value to base10 & then sum In base4 the places are 1, 4, 16, 64 So 3210 base4 = 3*64 + 2*16 + 1*4 = 228 In base 3 the places are 1, 3, 9,27 So 210 base 3 is 2*9 + 1*3 = 21 In base 2 the places are 1,2,4,8 So 10 base 2 = 1 * 2 = 2 So 228 + 21 + 2 = 251
Area = base x altitude /2 so base = 2 x area/altitude = 64/6 = 10 & 2/3 cm.
the base is the number you start with... like 8 squared... your base will be 8 and your square will be 2... that means 8 squared would be 8x8... = 64... hope this helps!!
64.2510 = 64 + 1/4 = 26 + 2-2 = 1000000.01 in base 2.
64
1/2 base x height so 1/2 B x 16 = 64. 1/2 of 16 is 8 and 64/8 = 8 so the base is 8 feet
The obvious answer is 5,000,000 but... If the 1000000 is in base 2 (binary) and the five is in base 10 (decimal) then 1000000 equals 64 in base 10; 64x5 = 320 which is 101000000 in base 2.
Since you can calculate this in any scientific calculator (or in Excel, typing: = 2^64), it really doesn't make sense to ask that here.
Convert each value to base10 & then sum In base4 the places are 1, 4, 16, 64 So 3210 base4 = 3*64 + 2*16 + 1*4 = 228 In base 3 the places are 1, 3, 9,27 So 210 base 3 is 2*9 + 1*3 = 21 In base 2 the places are 1,2,4,8 So 10 base 2 = 1 * 2 = 2 So 228 + 21 + 2 = 251
2^16th (hexadecimal) is 64 times larger than 2^1st (binary). They basically represent the same data otherwise.
Area = base x altitude /2 so base = 2 x area/altitude = 64/6 = 10 & 2/3 cm.
Let the hypotenuse be (x+2) and the height be x and use Pythagoras' theorem:- (x+2)2-x2 = 82 (x+2)(x+2)-x2 = 64 x2+4x+4-x2 = 64 4x+4 = 64 4x = 64-4 4x = 60 x = a height of 15 units Area = 1/2*base*height = 1/2*8*15 = 60 square units
the base is the number you start with... like 8 squared... your base will be 8 and your square will be 2... that means 8 squared would be 8x8... = 64... hope this helps!!
67=64+2+1 =26+21+20 =1000011
64 different whole numbers can be written with 6 bits.