For a three-dimensional del operator in Cartesian coordinates:
del2 = delT del = del dot del = d/dx2 + d/dy2 + d/dz2
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(-1.5,0) (1.5,0) what is the gradient?
Draw a tangent to the curve at the point where you need the gradient and find the gradient of the line by using gradient = up divided by across
I am not sure I understand what you are asking. The formula you give is a parabola and the gradient of the curve is changing all the time. So please can you give more details about where this acute angle might be.
9x squared-15x squared = -6
1 squared = 1 2 squared = 4 3 squared = 9 4 squared = 16 5 squared = 25 6 squared = 36 7 squared = 49 8 squared = 64 9 squared = 81 10 squared = 100