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On number line all the numbers are marked with equidistant spaces. Take a point A at origin(at 0) and point B on 1. This gives us AB = 1 unit.
Another point C is taken such that BC = 1 unit and BC is perpendicular to the number line.
If we join A to C then we get a right triangle and if we apply Pythagoras theorem, then we get:
AC2 = AB2 + BC2
AC2 = 12 + 12
AC = √2 units
With the help of divider measure AC and mark point D on number line such that AD = √2 units. (Take point D should be after B).
Another point E is taken such that DE = 1 unit and DE is perpendicular to number line.
And we get another triangle ADE and on applying Pythagoras theorem, we get
AE = √3 units
And again with the help of divider measure AE and take point F on number line such that AF = √3 units.
This way we get the value of √3.
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