y=16 x= -4
(2,-2)
Yes and it works out that x = 3 and y = 4
Double first equation: 2x + 2y = 4 Subtract this from second equation giving 5y = 5 so y = 1 and x = 1
2x-3y=13
y=16 x= -4
(2,-2)
Yes and it works out that x = 3 and y = 4
Double first equation: 2x + 2y = 4 Subtract this from second equation giving 5y = 5 so y = 1 and x = 1
2x-3y=13
Solving by the elimination method gives: x = 3 and y = 2
2x + 2y = 44x + y = 1There are many methods you can use to solve this system of equations (graphing, elimination, substitution, matrices)...but no matter what method you use, you should get x = -1/3 and y = 7/3.
it equals 13X.
x + 8y = 3 therefore 2x + 16y = 6 (a) 2x + 3y = -7 (b) Subtract (b) from (a): 13y = 13 so y = 1 and x = -5
It's a simultaneous equation and can be solved by elimination which works out as:- x = -4 and y = 1
how do you use the substitution method for this problem 2x-3y=-2 4x+y=24
x=1