The equation "x plus 2y equals 5" is: x + 2y = 5 2y = 5 - x y = 5/2 - 1/2x y = -1/2x + 5/2
2y + 2x = 20 y - 2x = 4 Add the two equations: 3y = 24 so that y = 8 Substitute this value of y in the second equation: 8 - 2x = 4 then 4 = 2x so that x = 2 Thus the ordered pair (y,x) = (8,2)
if x = 8in the equation y=2x/(4-2) -- y=8in the equation y=2x/4-2 -- y=2it really depends on how the equation is written, because that would depend on whether you divide or subtract firsty = ( (8^2) / (4) ) - 2y = ( (64) / (4) ) -2y = 16 -2y = 14
y=2x+4 --> x=2y+4 ==> y=(x-4)/2
Answers to pick: -2x - y = 4 2x + y = -2 -8x + 4y = -16 -4x + 2y = -8 -x - 2y = 6 -7x + 4y = 16 2x + 3y = 6 3x + 2y = 4
(3, 2)
x - 2y = -4 2x - y = 1 To solve this system of equations, I used matrices, and got x = 2 and y = 3.
If: 12 = 2y+x then y = -1/2x+6 So: y = 2x+4 and y = -1/2x+6 which means that they are perpendicular lines
(4, -1)
x= 3 and y = 2
16x - 2y = 74 (Eq 1) 2x - 2y = 4 (Eq 2) from Eq 2, 2y = 2x - 4 Substitute in Eq 1 16x - (2x - 4) =74 ie 16x - 2x + 4 = 74 ie 14x = 70 ie x = 5 2y = 2x - 4 = 10 - 4 = 6 y =3 Check 16 x 5 - 2 x 3 = 80 - 6 = 84 QED
-2x + 2y = 4 is equivalent to twice -2 + y = 2 which is the equation of a straight line.
-2X + 2Y = 4 2Y = 2X + 4 Y = X +2 by inspection, 2 but, you could also 0 out X in original equation -2(0) + 2Y = 4 2Y = 4 Y = 2
The equation "x plus 2y equals 5" is: x + 2y = 5 2y = 5 - x y = 5/2 - 1/2x y = -1/2x + 5/2
It doesn't look like you have anything that can be determined. The most confusing part of this is the -2x 2y = -4
The ordered pair is (3, 2).
The ordered pair is (2, 3).