(4y + 1)(3y + 2)
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23y-11y = 12y
y(3y^2 - 12y + 4)
2y2 + y = -11yAdd 11y to each side of the equation:2y2 + 12y = 0Divide each side by 2:y2 + 6y = 0Factor the left side:y (y + 6) = 0The equation is true if either factor is zero:y = 0or (y + 6) = 0y = -6
Pull out the common factor of 2 ... 2(y^2+6y-16) Then just factor (y^2+6y-16) ... (y-2)(y+8)
4(3y+4)