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Q: How do you factor 12y plus 9?

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12y3 - 30y2 + 12yFactor out a y:y(12y2 - 30y + 12)Factor out a 6:6y(2y2 -5y + 2)Factor 2y2 - 5y + 26y(2y - 1)(y - 2)

factor the trinomial 16x^2+24x+9

-5x + y = -12- 3x + 6y = -12Since both of expressions have a value of -12, their sum is - 24. This is true only whenx = 20/9 and y = -8/9.-5x + y = -12y = 5x - 12- 3x + 6y = -12-3x + 6(5x - 12) = -12-3x + 30x - 72 = -1227x = 60x = 60/27x = 20/9y = 5x - 12y = 5(20/9) - 12y = 100/9 - 12y = (100 - 108)/9y = -8/9

18b+9=9(b+2)

y2 + 12y + 5y + 60 y (y + 12) + 5 (y + 12) (y + 12 )(y + 5)

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y^2 - 12y + 36 = 9 subtract 9 from each side y^2 - 12y + 27 = 0 easy factoring by inspection (y - 3)(y - 9) y = 3 y = 9

12y + 5 = 53 12y = 48 y = 4

I assume the expression is y2+12y+27 as I cannot see the operation symbols between them (editor problem?). If you agree with this then y2 + 12y + 27 = y2 + 9y + 3y + 27 = y(y + 9) + 3(y + 9) = (y + 3)(y + 9)

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