Q: How will you find the solution of this quadratic equation by factoring 2y squared plus y equals negative 11y?

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To find the solution to this equation, you need to rearrange the terms and solve for the variable. 4 = 2b + b^2 can be rewritten as b^2 + 2b - 4 = 0. You can then solve this quadratic equation by factoring, completing the square, or using the quadratic formula.

Draw the graph of the equation. the solution is/are the points where the line cuts the x(horisontal) axis .

Sum

When you graph the quadratic equation, you have three possibilities... 1. The graph touches x-axis once. Then that quadratic equation only has one solution and you find it by finding the x-intercept. 2. The graph touches x-axis twice. Then that quadratic equation has two solutions and you also find it by finding the x-intercept 3. The graph doesn't touch the x-axis at all. Then that quadratic equation has no solutions. If you really want to find the solutions, you'll have to go to imaginary solutions, where the solutions include negative square roots.

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Related questions

If you have a quadratic equation and there is no x to put into the equation to get zero. The graph is like a U that is above the x axis or a cap that is below the x axis.

To find the solution to this equation, you need to rearrange the terms and solve for the variable. 4 = 2b + b^2 can be rewritten as b^2 + 2b - 4 = 0. You can then solve this quadratic equation by factoring, completing the square, or using the quadratic formula.

Draw the graph of the equation. the solution is/are the points where the line cuts the x(horisontal) axis .

Sum

When you graph the quadratic equation, you have three possibilities... 1. The graph touches x-axis once. Then that quadratic equation only has one solution and you find it by finding the x-intercept. 2. The graph touches x-axis twice. Then that quadratic equation has two solutions and you also find it by finding the x-intercept 3. The graph doesn't touch the x-axis at all. Then that quadratic equation has no solutions. If you really want to find the solutions, you'll have to go to imaginary solutions, where the solutions include negative square roots.

x2

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Is it possible for a quadratic equation to have no real solution? please give an example and explain. Thank you

If the discriminant of a quadratic equation is less than zero then it has no solutions.

Whether or not that there is a solution to a quadratic equation,

It has one real solution.

In basic mathematics, a quadratic equation with a negative discriminant has no solutions. However, at a more advanced level you will learn that it has two solutions which form a complex conjugate pair.