To factorise this completely you need to be aware that 216 = 63. (x3 + 216) = (x + 6)(x2 - 6x + 36)
x(6x - 11)
(x - 6)(x2 + 6x + 36)
-x(x2 - 2)(x2 + 3)
x2+6x-7 = (x+7)(x-1) when factored
x2-6x-27 = (x+3)(x-9) when factored
X2 - 6X + 27 = 0 what are the factors of 27 that add to - 6? None! This polynomial is unreal and does not intersect the X axis.
x2 - 6x - 27 = (x-9)(x+3)
(x - 9)(x + 3)
please help on this x2+6x+27=
x2 + 6x - 2 can not be factored
x2 + 6x - 27 = (x + 9)(x - 3)
This doesn't have an "answer" per se, as it is not a question or even an equation. If you're looking to factor the expression, then here's how it can be done: x2 + 6x - 27 = x2 + 9x - 3x - 27 = x(x + 9) - 3(x + 9) = (x - 3)(x + 9)
x2-6x can be factored into x(x-6). Simply factor out the "x" from both factors.
4
x2 + 6x + 8 = (x + 4)(x + 2)
x2-6x+9 = (x-3)(x-3) when factorised.