How do you factor 20x2 plus 22x-12?

Answer 1

20x^2 + 22x - 12

Since '2' is a common factor

Then

2(10x^2 + 11x -6)

To factor the bracket bit , we write down all the factors of '10' & '6'

Hence

10 ; 1,2,5,10,

6 ; 1,2,3,6.

We then select a pair of numbers from each factors to multiply together and then add/subtract to reach '11'.

They are ( 2,5) & ( 2,3)

3 x 5 = 15 & 2 x 2 = 4

15 - 4 = 11

So (2,3) & ( 2,5) are the selected factors.

Open brakets. ( 5x 2)(2x 3)

To select the signs, we note that '6' is a minus '-6' , so the signs are differen(+/-).

We also note that 11x is positive (+) , so the larger multiple is the positive multip;le and the small is the negative.

Hence

(5x - 2)(2x + 3)

Overall it is

2(5x - 2)(2x + 3)

Answer 2

Dividing all terms by 2 gives: 10x2+11x-6 = (5x-2)(2x+3) when factored