4(w^2 + 3w + 1)
39 + 12w = 1039 -10 = -12w29 = -12ww = -12/29 = -0.413
-8w-7x
Assuming this question is asking about a rectangle: Perimeter = 2l + 2w and according to this problem Perimeter = 96, so 96 = 2l + 2w If l = 5w, then we can replace each l in the statement above with 5w, so 96 = 2(5w) + 2w 96 = 10w + 2w 96 = 12w 8 = w If 8 = w, and l = 5w, then l = 5 times 8 = 40 The area of a rectangle is length (l) times width (w), so A = lw A = (40) (8) A = 320 square units
Let the width be ( w ). Then, the length is ( 5w ). The formula for the perimeter ( P ) of a rectangle is ( P = 2(\text{length} + \text{width}) ). Substituting the known values, we have ( 3600 = 2(5w + w) ), which simplifies to ( 3600 = 12w ). Therefore, the width ( w ) is ( 3600 / 12 = 300 ) meters.
Let the width of the storm window be ( w ) inches. Then the height would be ( w + 12 ) inches. The area of the window can be expressed as ( w(w + 12) = 448 ). Solving the equation ( w^2 + 12w - 448 = 0 ) gives ( w = 16 ) inches (width) and ( h = 28 ) inches (height), so the dimensions of the window are 16 inches wide and 28 inches high.
39 + 12w = 1039 -10 = -12w29 = -12ww = -12/29 = -0.413
It is 12w = 48 or w = 4.
It is 12w.
12x+12y-12w
6(2w + 1)
12x-14w+103y+72+16-56+0-65+2w+0 original = 12x-14w+2w+103y+72+16-56+0-65+0 group = 12x-12w+103y-33 answer
20
When you have a lagging power factor, measuring instruments (i.e. AC energy meters etc..) will read high. For example, if you've actually used 12W, when a lagging power factor is present, the meter might read 13~14W.
One Stop Plus has a lot of clothing on sale and their size ranges from 12W to 44W. Simply Be has a smaller range from 10W to 28W, but they offer 30% off your first order.
The brightness level of a 12W LED equivalent bulb is typically around 800 lumens, which is similar to a 60W incandescent bulb.
The product of w and 12 is 12w.
4