4x2+4x-8 4(x2+x-2) and (4x+8)(x-1)
(4x + 5)(x - 3)
4x(4x^2 + 3x + 1)
2(x - 1)(2x + y)
No solution in integers.
4x2+4x-8 4(x2+x-2) and (4x+8)(x-1)
(4x - 7y)(4x + 7y)
4x times 4x equals 16x2.
4x squared
(4x + 5)(x - 3)
The derivative of 2x2 + 4x + 8 is 4x+4.
(2x-1)(2x-1) = 4x^2 -4x + 1
x(x-4)
No
4x(4x^2 + 3x + 1)
Remember both 16 & 25 are squared numbers. 16 = 4^2 & 25 = 5^2 Hence we can write (4x)^2 - (5y)^2 Remember two squared terms with a NEGATIVE Between them will factor. ( 4x - 5y)(4x + 5y) Note the difference signs. NNB Two squared terms with a positive (+) between them DOES NOT factor.
2(x - 1)(2x + y)