0
Anonymous
That depends on what you're doing to the 8.
It's either 4(x2 + 2) or 4(x2 - 2)
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4x2+4x-8 4(x2+x-2) and (4x+8)(x-1)
(4x + 5)(x - 3)
4x(4x^2 + 3x + 1)
2(x - 1)(2x + y)
No solution in integers.