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4y2+25y+6 = (4y+1)(y+6) when factored with the help of the quadratic equation formula
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TaigaTo factor 4y^2 + 25y + 6, you can split the middle term by finding two numbers whose product is equal to 4 * 6 (the product of the first and last terms) and whose sum is equal to the coefficient of the middle term, which is 25. In this case, the numbers are 4 and 1. So, you can rewrite the expression as (4y + 1)(y + 6).
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How do you simplify 4y2 plus 25y plus 6?
4y2 + 25y + 6
How do you factor 4y2 25y 6?
Assuming the missing signs are pluses, that factors to (4y + 1)(y + 6)
What is y in x equals 4y2 plus 6 when x equals 42?
In the equation x = 4y2 + 6 where x = 42, we need to substitute 42 for x and solve for y. x = 4y2 + 6 42 = 4y2 + 6 42 - 6 = 4y2 + 6 - 6 36 = 4y2 36 / 2 = 4y2 / 2 18 = 4y 18 / 4 = 4y / 4 9 / 2 = y 4 1/2 = y (or 4.5 = y)
How do you find the solution to x2 - 20xy plus 4y2?
If you're looking to factor this expression, then you need to find two values that add up -20, and which multiply to make 4. Unfortunately, no such terms exist, so this expression can not be factored.
What is the factors for 25y squared minus 36?
(5y - 6)(5y + 6)
