There are four possibilities depending on the missing operational signs:
4y2 + 2y + 6 factors to 2(2y2 + y + 3)
4y2 + 2y - 6 factors to 2(y - 1)(2y + 3)
4y2 - 2y - 6 factors to 2(y - 1)(2y - 3)
4y2 - 2y + 6 factors to 2(2y2 - y + 3)
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2y2-2y-4 = (2y-4)(y+1) when factored
8(2y^3 - z^2)(4y^6 + 2y^3z^2 + z^4)
x(y-10)+6(y-10) ^^^that's the first step, then: the x and 6 pair together, and one of the (y-10) leaves the expression so it becomes: (x+6)(y-10) this is referred to as Factoring by Grouping
Six factors: 1 2 4 13 26 52.
If that's + 2y, the answer is (y + 4)(y - 2)