4y2 + 25y + 6
The expression in the question does not define an area.
(2y-11)^2
4(y + 2)(y + 2)
In the equation x = 4y2 + 6 where x = 42, we need to substitute 42 for x and solve for y. x = 4y2 + 6 42 = 4y2 + 6 42 - 6 = 4y2 + 6 - 6 36 = 4y2 36 / 2 = 4y2 / 2 18 = 4y 18 / 4 = 4y / 4 9 / 2 = y 4 1/2 = y (or 4.5 = y)
4y2 + 25y + 6
(4y2 + 3)(4y2 - 6y + 3)(4y2 + 6y + 3)
The expression in the question does not define an area.
(2y-11)^2
(4y + 1)(y + 6)
4(y + 2)(y + 2)
(y - 5)(4y - 5)
In the equation x = 4y2 + 6 where x = 42, we need to substitute 42 for x and solve for y. x = 4y2 + 6 42 = 4y2 + 6 42 - 6 = 4y2 + 6 - 6 36 = 4y2 36 / 2 = 4y2 / 2 18 = 4y 18 / 4 = 4y / 4 9 / 2 = y 4 1/2 = y (or 4.5 = y)
4(y + 2)(y + 2)
(2y + 3)(4y2 - 6y +9)
(4y - 1)(y + 2)
4y2+16y+16=0 Divide by 4 on both sides: y2+4y+4=0 Factorise: (y+2)(y+2)=0 Therefore y= -2