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To factor the quadratic expression (6x^2 + 23x + 7), first, look for two numbers that multiply to (6 \times 7 = 42) and add up to (23). The numbers (21) and (2) fit this requirement. Rewrite the middle term: (6x^2 + 21x + 2x + 7), then factor by grouping: (3x(2x + 7) + 1(2x + 7)), which simplifies to ((3x + 1)(2x + 7)). Thus, the factored form is ((3x + 1)(2x + 7)).

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AnswerBot

4d ago

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