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Simplifying
6x2 + 23x + 7
Reorder the terms:
7 + 23x + 6x2
Factor a trinomial.
(7 + 2x)(1 + 3x)
Final result:
(7 + 2x)(1 + 3x)
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∙ 14y ago
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Factor 6X2 minus 23X plus 7?
(3x - 1)(2x - 7)
How do you factor 45x2 plus 23x - 56?
(9x - 8)(5x + 7)
Factor the expression 6x2 plus 11g-35?
(3x - 5)(2x + 7)
-3x3-6x2 plus 189x factor completely?
-3x3 - 6x2 + 189x = -3x(x2 + 2x - 63) = -3x(x + 9)(x - 7)
What is 6x2-17x plus 7 factored?
6x2-17x+7 = (2x-1)(3x-7) when factored
What is 7 plus 24 divided by (6x2)?
7 + 24 ÷ (6x2) =7 + 24 ÷ 12 = 7 + 2 = 9
Factor the trinomial 6x2 - 13x - 63?
6x2 - 13x - 63 = 6x2 + 14x - 27x - 63 = 2x(3x + 7) - 9(3x + 7) = (3x + 7)(2x - 9)
How do you factor 6x2-13x-63?
(3x + 7)(2x - 9)
How do you factor the trinomial completely 30x2-23x-14?
30x2-23x-14 = (6x-7)(5x+2) when factored with the help of the quadratic equation formula
How do you factor 6x2 plus 2x 28?
I'll assume that that should read: 6x2 + 2x - 28 Then: First take out a common factor of 2: 6x2 + 2x - 28 = 2(3x2 + x - 14) The coefficient of the x2 is 3 and can only be factored as 3 x 1 (and 1 x 3) which means that 3x must be in one factor and x in the other. The other element of each factor is a factor of -14 which can be factorised as: -1 x 14, -2 x 7, -7 x 2 & -14 x 1. Need three times one factor plus the other factor = +1 (the coefficient of the x) Inspection shows that (3 x -2) + 7 = -6 + 7 = 1 works; so put the factor multiplied by 3 with the x and the other factor with the 3x, giving: 2(3x2 + x - 14) = 2(3x + 7)(x - 2)
What is the solution for -23x-23x 4-7?
Are those x's or multiplication signs?
How do you write an equation of a line that passes through the point 7 3 and is parallel to the line Y -2 3x plus 3?
If you mean: y = -23x+3 then the parallel equation is y = -23x+164
