(3x - 1)(2x - 7)
(9x - 8)(5x + 7)
(3x - 5)(2x + 7)
-3x3 - 6x2 + 189x = -3x(x2 + 2x - 63) = -3x(x + 9)(x - 7)
6x2-17x+7 = (2x-1)(3x-7) when factored
7 + 24 ÷ (6x2) =7 + 24 ÷ 12 = 7 + 2 = 9
6x2 - 13x - 63 = 6x2 + 14x - 27x - 63 = 2x(3x + 7) - 9(3x + 7) = (3x + 7)(2x - 9)
(3x + 7)(2x - 9)
30x2-23x-14 = (6x-7)(5x+2) when factored with the help of the quadratic equation formula
I'll assume that that should read: 6x2 + 2x - 28 Then: First take out a common factor of 2: 6x2 + 2x - 28 = 2(3x2 + x - 14) The coefficient of the x2 is 3 and can only be factored as 3 x 1 (and 1 x 3) which means that 3x must be in one factor and x in the other. The other element of each factor is a factor of -14 which can be factorised as: -1 x 14, -2 x 7, -7 x 2 & -14 x 1. Need three times one factor plus the other factor = +1 (the coefficient of the x) Inspection shows that (3 x -2) + 7 = -6 + 7 = 1 works; so put the factor multiplied by 3 with the x and the other factor with the 3x, giving: 2(3x2 + x - 14) = 2(3x + 7)(x - 2)
Are those x's or multiplication signs?
If you mean: y = -23x+3 then the parallel equation is y = -23x+164