(a + 3)( b + 2)
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ab + 2a + 3b + 6
Answer = 20 Let the number be ab where a is the "tens" value and b is the "units" value. Then a + 4 = 3(a + b) a + 4 = 3a + 3b 4 = 2a + 3b The only condition that satisfies this is when b = 0 then 4 = 2a : a = 2
ab + 4 + a + 4b factors to (a + 4)(b + 1)
(a + b)(b - 2c)
(b - x)(ab - xy)