(a + b)(b + c)
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ab-2ac+b^2-2bc
This expression can be factored. ab + 3a + b2 + 3b = a(b + 3) + b(b + 3) = (a + b)(b + 3)
(a+b+c) (a+b-c)
= (a + b)2 or (a + b)(a + b) (a + b)(a + b) using the FOIL method yields: [multiplying {First Outer Inner Last} and summing the products] = a.a + a.b + b.a + b.b = a2 + ab + ab + b2 = a2 + 2ab + b2
(b + 2)(b + 2) or (b + 2)2