ab-2ac+b^2-2bc
This expression can be factored. ab + 3a + b2 + 3b = a(b + 3) + b(b + 3) = (a + b)(b + 3)
(a+b+c) (a+b-c)
= (a + b)2 or (a + b)(a + b) (a + b)(a + b) using the FOIL method yields: [multiplying {First Outer Inner Last} and summing the products] = a.a + a.b + b.a + b.b = a2 + ab + ab + b2 = a2 + 2ab + b2
(b + 2)(b + 2) or (b + 2)2
6(ab - ac + b2 - bc)
ab-2ac+b^2-2bc
(a + b)(b - 2c)
(a + b)(b - 2c)
a(b+3)+b(b+3)
b2 + ab - 2 - 2b2 + 2ab = -b2 + ab - 2 which cannot be simplified further.
a3 + b3 = (a + b)(a2 - ab + b2) a3 - b3 = (a - b)(a2 + ab + b2)
6(b - ac + b2 - bc)
(a+b+c) 2=a2+ab+ac+ba+b2+bc+ca+cb+c2a2+b2+c2+2ab+2bc+2ca [ ANSWER!]
(a3 + b3)/(a + b) = (a + b)*(a2 - ab + b2)/(a + b) = (a2 - ab + b2)
The GCF is a2b.
Sum and difference of two cubes is factored this way : a3 + b3 = (a + b)(a2 - ab + b2) a3 - b3 = (a - b)(a2 + ab + b2)