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Q: Factor ab plus 3a plus b2 plus 3b?

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This expression can be factored. ab + 3a + b2 + 3b = a(b + 3) + b(b + 3) = (a + b)(b + 3)

(a + 3)( b + 2)

The GCF is a.

(b + 3)(a + c)

0

a(3+b)+c(3+b) * * * * * This is easy to finish: . . . = (a + c)(3 + b).

The factors of 3a are 3 and a. The factors of 6c are 6 and c. The factors of ab are a and b.

That factors to (b + 3)(a + c)

ab + 2a + 3b + 6

so let's group and then factor ab+2a+3b+6= (ab+2a)+(3b+6)= a(b+2)+3(b+2)= (a+3)(b+2) and that is our final answer! Doctor Chuck

(a - 2)(b + 3)

ab-2ac+b^2-2bc

(a + b)(b + c)

You want: abc + ab Factor out the common terms which are "a" and "b" ab ( c + 1 )

x2y + axy + abx + a2b Factor by grouping. xy(x + a) + ab(x + a) (xy + ab)(x + a)

ab + 4 + a + 4b factors to (a + 4)(b + 1)

No, A person with AB- can receive from O-, A-, B-, or AB-. See chart on related link. A positive Rh factor can receive from a negative, but not the other way around.

(a + b)(b - 2c)

(a - c)(b - d)

(a + b)(b - 2c)

(a+b)(a squared-ab+b squared)

(b - x)(ab - xy)

e a cd

4

a and b are factors of ab