6x3 + 9x2 - 2x2 - 3x Before any grouping, take out the common factor, x, to give x*(6x2 + 9x - 2x - 3) = x*[3x*(2x + 3) - 1*(2x + 3)] = x*(2x + 3)*(3x - 1)
(-3x - 1)(3x - 7)
(3x + 1)(x + 5)
(x + 5)(3x + 1)
3x(2y + 1)
3 - 3x + x2 - x3 = (1 - x)(x2 + 3)
6x3 + 9x2 - 2x2 - 3x Before any grouping, take out the common factor, x, to give x*(6x2 + 9x - 2x - 3) = x*[3x*(2x + 3) - 1*(2x + 3)] = x*(2x + 3)*(3x - 1)
3X + 8You don't factor this as there are no common factors.
(-3x - 1)(3x - 7)
15x - 3xy = 3x(5 - y) 20 - 4y = 4(5 - y) 15x - 3xy + 20 - 4y = (3x + 4)(5 - y)
3(x2 + 3x + 1)
(3x + 1)(x + 5)
(x + 5)(3x + 1)
It is: 3x*(x+7)
3x(2y + 1)
(3x + 5)(3x^2 + 4)
(3x + 4)(3x + 4)