9x2 + 6x + 1 = 9x2 + 3x + 3x + 1 = 3x(3x + 1) + 1(3x + 1) = (3x + 1)(3x + 1) or (3x +1)2
it is a combination of perfect squares the square of 9x is squared is +/- 3x, and the square of 4 is +/- 2 so the answer is (3x+2)(3x-2) which is 9xsquared-6x+6x-4 =9xsquared-4
9x2 + 9x - 10 =(3x - 2)(3x + 5)
In one bracket, write 16 times the square root of 2 minus 3x. In the other one, write 16 times the square root of 2 plus 3x.
factor out a 3x 3x(x-3)=3x2-9x
(3x - y+ 2)(3x + y + 2)
(x + 3)(3x - 2)
Let the symbol ^ mean "to the power" Then 9x^2 + 24x + 16 = (3x + 4)(3x +4) = (3x + 4)^2
Step 1: Divide by 9x: 9x (x2 + 3x - 10) = 9x(x + 5)(x - 2)
(3x-4)(3x+4)
the answer is (3x-2)(9x squared+6x+4)
(3x + 8)(3x - 8)
(x + 2)(3x - 1)(3x + 1)
It is a difference of squares. 9x^2-49=(3x+7)(3x-7)
It can't be factored because the discriminant of this quadratic expression is less than zero.
10
9x2...I guess that means 9x squared ? The problem: 9x(squared)+12x+4 Here's the answer: (3x+2)(3x+2) or even more simplified: (3x+2) squared