Q: How do you Factor 3X squared plus 9X plus 3?

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9x2 + 6x + 1 = 9x2 + 3x + 3x + 1 = 3x(3x + 1) + 1(3x + 1) = (3x + 1)(3x + 1) or (3x +1)2

it is a combination of perfect squares the square of 9x is squared is +/- 3x, and the square of 4 is +/- 2 so the answer is (3x+2)(3x-2) which is 9xsquared-6x+6x-4 =9xsquared-4

9x2 + 9x - 10 =(3x - 2)(3x + 5)

In one bracket, write 16 times the square root of 2 minus 3x. In the other one, write 16 times the square root of 2 plus 3x.

factor out a 3x 3x(x-3)=3x2-9x

Related questions

(3x - y+ 2)(3x + y + 2)

(x + 3)(3x - 2)

Let the symbol ^ mean "to the power" Then 9x^2 + 24x + 16 = (3x + 4)(3x +4) = (3x + 4)^2

Step 1: Divide by 9x: 9x (x2 + 3x - 10) = 9x(x + 5)(x - 2)

(3x-4)(3x+4)

the answer is (3x-2)(9x squared+6x+4)

(3x + 8)(3x - 8)

(x + 2)(3x - 1)(3x + 1)

It is a difference of squares. 9x^2-49=(3x+7)(3x-7)

It can't be factored because the discriminant of this quadratic expression is less than zero.

10

9x2...I guess that means 9x squared ? The problem: 9x(squared)+12x+4 Here's the answer: (3x+2)(3x+2) or even more simplified: (3x+2) squared