If that's -18y2, the answer is (3x - 2y)(x + 9y)
6x2 + 10x = 2x*(3x + 5)
-15x2+5x=-5x(3x-1)
5x(3x + 1)
x(3x - 2)
3x2-21x+36 =3(x2-7x+12) =3(x-4)(x-3)
3x+21x+9x=33x. Break it apart. The factor of x is x and the factors of 33 are 3 and 11. Therefore, the factors of 3x+21x+9x are 3, 11, and x.
y = 3x + 21x2 = 3x(1 + 7x)
To factor the expression 21x^35, you need to find the common factors of 21 and x^35. The factors of 21 are 1, 3, 7, and 21. The factors of x^35 are x, x^2, x^3, ..., x^35. Therefore, the factored form of 21x^35 is 21x*x^34 or 21x^(35-1).
(3x - y+ 2)(3x + y + 2)
3(x2 + 3x + 1)
(3x + 1)(x + 5)
(x + 5)(3x + 1)
If that's -18y2, the answer is (3x - 2y)(x + 9y)
(3x + 3y)(x + y) = 3(x + y)2
(6x + t)(3x + t)
3x(2x + 1)