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This question involves a property of dividing common bases. For example, xm/xn is the same as saying x(m-n). Whenever two common bases are being divided, the exponents can be combined by subtraction.

So, for this problem: e(2x-1)/e(x-1), the e can be written once, with the exponents being subtracted:

e2x-1-(x-1), distributing the minus sign arrives at e2x-1-x+1, or ex.

ANS: ex

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15y ago

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