(2x - 1)(2x + 1)
(x - 1)(x + 1)
9(2x - 1)(2x + 1)
(4x + 1)(2x + 3)
Factor out the GCF and get X(X2-X+1).
(x - 1)(5x + 7)
(2x - 1)(4x + 1)
(2x-1)(2x-1) = 4x^2 -4x + 1
2x(2x - 1)
4(x - 1)(x + 1)
There is no rational factorisation.
8x2-10x-3 = (2x-3)(4x+1) when factored
Find factors of -5 that can be added to make -4, in this case -5 and 1, so: (x - 5)(x + 1) = x2 - 4x - 5
4x2+4x-8 4(x2+x-2) and (4x+8)(x-1)
8x^2 + 6x - 5 = 8x^2 + 10x - 4x - 5 = 2x * (4x + 5) - (4x + 5) = (2x -1) * (4x + 5)
To factor the quadratic expression (4x^2 - x - 5), we look for two numbers that multiply to (4 \times -5 = -20) and add to (-1) (the coefficient of (x)). The numbers (-5) and (4) work since (-5 + 4 = -1). We can then rewrite the expression as (4x^2 - 5x + 4x - 5) and factor by grouping: (x(4x - 5) + 1(4x - 5)), yielding ((4x - 5)(x + 1)). Thus, the factored form is ((4x - 5)(x + 1)).
X2 - 4X - 5 = 0 easy factor, what two factors of - 5 add up to - 4 (X + 1)(X - 5) X = - 1 ------------- X = 5 --------------
It is (A-1)(A+1) when factored