mn - 4m - 5n + 20 = m(n - 4) - 5(n - 4) = (n - 4)(m - 5)
Let the number be 'm' & 'n' Hence Sum = m + n = -5 Product = mn = 4 Algebraically rearrange the product to m = 4/n Substitute into the Sum (4/n) + n = -5 Multiply through by 'n' Hence 4 + n^2 = -5n n^2 + 5n + 4 = 0 It is not in Quadrtatic form . to solve. Hence (n - 1)(n - 4) = 0 n = -1 & n = -4 Are the two numbers.
MN is not an abbreviation for millions.
To factorize 30m^2n, you need to find the common factors of each term. From 30, you can take out a common factor of 2 and from m^2n you can take out a common factor of mn. Therefore, the factored form of 30m^2n is 2mn(15m).
1 m or 1M, and less commonly, 1 mn or 1 Mn.
mn - 4m - 5n + 20 = (mn - 5n) - (4m - 20) = n(m - 5) - 4(m - 5) = (m -5)(n - 4)
mn - 4m - 5n + 20 = m(n - 4) - 5(n - 4) = (n - 4)(m - 5)
a^2-a-20
(m - 5)(n - 4)
mn - 15 + 3m - 5n Rearranging: mn + 3m - 5n - 15 = m(n + 3) - 5(n + 3) = (m - 5)*(n + 3)
The GCF is 5n.
The GCF is MN.
They are 1, 2, 4, m, 2m, 4m, n, 2n, 4n, mn, 2mn and 4mn.
11
m(n + 1)
-mn(m - n2)(m + n2)
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