(m - 5)(n - 4)
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mn - 4m - 5n + 20 = m(n - 4) - 5(n - 4) = (n - 4)(m - 5)
MN is not an abbreviation for millions.
Let the number be 'm' & 'n' Hence Sum = m + n = -5 Product = mn = 4 Algebraically rearrange the product to m = 4/n Substitute into the Sum (4/n) + n = -5 Multiply through by 'n' Hence 4 + n^2 = -5n n^2 + 5n + 4 = 0 It is not in Quadrtatic form . to solve. Hence (n - 1)(n - 4) = 0 n = -1 & n = -4 Are the two numbers.
To factorize 30m^2n, you need to find the common factors of each term. From 30, you can take out a common factor of 2 and from m^2n you can take out a common factor of mn. Therefore, the factored form of 30m^2n is 2mn(15m).
1 m or 1M, and less commonly, 1 mn or 1 Mn.