That doesn't factor neatly. Applying the quadratic equation, we find two imaginary solutions: (5 plus or minus the square root of -15) divided by 2.
x = 2.5 + 1.9364916731037085i
x = 2.5 - 1.9364916731037085i
where i is the square root of negative one.
(x - 10)(x - 10)
(y + 5) (y + 2)
(x + 10)(x + 3)
10x+10y+100 There is a common 10 in each number. 10(x+y+10)
(x + 5)(x^2 + 2x + 2)
1.6667
10 + 9x
1
10c + 10The only common factor is 10, and this can be divided out, resulting in:10(c+1)
(2x - 1)(x - 10)
(x - 10)(x - 10)
(x + 10)(x + 2)
5(x + 2 + 3y)
(y + 5) (y + 2)
(x + 1)(3x + 10)
It is: 5(a+b)
(x + 10)(x + 3)