10c + 10
The only common factor is 10, and this can be divided out, resulting in:
10(c+1)
15b + 13c - 12b + 10c + 8 = 3b + 23c + 8
10 + 9x
(x + 1)(3x + 10)
3x2+13x-10 = (3x-2)(x+5) when factored
2(2x^2 + 2x - 5)
20c x 7, plus 10c x 1 20c x 6, plus 10c x 3 20c x 5, plus 10c x 5 20c x 4, plus 10c x 7 20c x 3, plus 10c x 9 20c x 2, plus 10c x 11 20c x 1, plus 10c x 13
To factorise the expression (70a - 20b - 10c), first identify the greatest common factor (GCF) of the coefficients, which is 10. Then, factor out 10 from the entire expression: [ 70a - 20b - 10c = 10(7a - 2b - c). ] Thus, the factorised form is (10(7a - 2b - c)).
In the algebraic expression (7a + 17b - 10c), the numbers 7, 17, and -10 are coefficients of the variables (a), (b), and (c), respectively. A coefficient is a numerical factor that multiplies a variable in an expression. Therefore, 7 is the coefficient of (a), 17 is the coefficient of (b), and -10 is the coefficient of (c).
Well, well, well, aren't we feeling fancy with our quadratic equations? To factor c squared plus 10c plus 25, you simply recognize that it's a perfect square trinomial that factors into (c + 5)^2. So, there you have it, all neat and tidy, just like your math skills.
A trinomial.
15b + 13c - 12b + 10c + 8 = 3b + 23c + 8
-10
10 + 9x
1
10
50cp+5pw-4wz-40cz 5p(10c+w)-4z(10c+w) (5p-4z)*(10c+w)
NO,because in quadratic equation highest power of a variable is 2. e.x. 4x2-20x+10=0.