15b + 13c - 12b + 10c + 8 = 3b + 23c + 8
10 + 9x
(x + 1)(3x + 10)
3x2+13x-10 = (3x-2)(x+5) when factored
2(2x^2 + 2x - 5)
20c x 7, plus 10c x 1 20c x 6, plus 10c x 3 20c x 5, plus 10c x 5 20c x 4, plus 10c x 7 20c x 3, plus 10c x 9 20c x 2, plus 10c x 11 20c x 1, plus 10c x 13
C2 + 10C + 25 The expression is a perfect square, so both factors are the same. (C + 5) and (C + 5)
A trinomial.
15b + 13c - 12b + 10c + 8 = 3b + 23c + 8
-10
10 + 9x
1
10
50cp+5pw-4wz-40cz 5p(10c+w)-4z(10c+w) (5p-4z)*(10c+w)
NO,because in quadratic equation highest power of a variable is 2. e.x. 4x2-20x+10=0.
-60 - 17 + (4-1)d + (10-2)c = -77 + 3d + 8c.
(2x - 1)(x - 10)