You don't!
There are no common factors.
(x+1)(x+8)
To factor the quadratic expression (x^2 + 7x - 8), we need to find two numbers that multiply to (-8) (the constant term) and add to (7) (the coefficient of the linear term). The numbers (8) and (-1) satisfy these conditions. Thus, we can factor the expression as ((x + 8)(x - 1)).
8(x + 1)
8(a + 3)
(b + 8)(b + 4)
x2 + 6x + 8 =(x + 2)(x +4)
the answer is (3x-2)(9x squared+6x+4)
(x+1)(x+8)
To factor the quadratic expression (x^2 + 7x - 8), we need to find two numbers that multiply to (-8) (the constant term) and add to (7) (the coefficient of the linear term). The numbers (8) and (-1) satisfy these conditions. Thus, we can factor the expression as ((x + 8)(x - 1)).
(x - 8)(3x + 4)
8(x + 1)
It is: 8n(5n+8)
8(a + 3)
(b + 8)(b + 4)
5x(6x + 7y + 8)
(2x - 1)(5x + 8)
(b + 8)(b - 1)