Best Answer

2m^2 - 8 = 2(m^2 - 4) = 2(m-2)(m+2).

A difference of squares, x^2 - y^2 say (or m^2 - 2^2 above), factorises as (x - y)(x + y).

Q: How do you factor using two m squared minus eight?

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It is: (3x+4)(2x-3) when factored

Using the quadratic formula you get z≅4.91547594742265 or z≅-0.91547594742265

X= plus or minus 1

If you mean: x squared -x -56 = 0 then using the quadratic equation formula x = 8 or x = -7

No.

Related questions

It is: (3x+4)(2x-3) when factored

If you are looking for the zeros of this function: x = -2 plus or minus 2 X the square root of 5.

Using the quadratic formula you get z≅4.91547594742265 or z≅-0.91547594742265

X= plus or minus 1

Using the quadratic formula-- ((negative b plus or minus the square root of b squared minus 4ac) divided by (2a)) you'll want to google that so you can see it in numerical form. a, b, and c are the coefficiants of your three terms ( 2 is a, -5 is b, and 2 is c) The answer is (x-2)(2x-1).

If you mean: x squared -x -56 = 0 then using the quadratic equation formula x = 8 or x = -7

No.

Solve using the quadratic formula

It can be solved by using the quadratic equation formula.

8-7

As an example, the product of (a + b) (a - b) is equal to a squared - b squared."Special product" simply means that there are special cases, when multiplying polynomials, that are worth memorizing. For example, if you know the above, then you can easily start factoring any expression that contains the difference of two perfect squares - for example, x squared minus 1, a to the power 6 minus b to the power 4, or even - if you start using complex numbers - a squared + b squared = a squared - (-1) b squared.

c^2 + c - 56 = (c - 7)(c + 8) using the factoring rule: c -7 -7c x x + c 8 8c c^2 -56 c