If your Problem is organized like this: A x squared plus B x plus C, the equation is: (B plus or minus the square root of(B squared minus 4 A C)) over 2A
The formula for finding the angles is called " Pythagorean Thyrum " It states that a squred plus b squared equals c squared so therefore c squared minus a squared will equal b squared. i hope that helps
No, unless "a" happens to be equal to 0, or to 1.
All the time
Use (-b + or - sqrt(b^2-4ac))/(2a) A is 10 B is -9 C is -6
B squared equals c squared minus a squared then to find B take the square root of you answer for b squared
(b-c)(a+b)-ac
If your Problem is organized like this: A x squared plus B x plus C, the equation is: (B plus or minus the square root of(B squared minus 4 A C)) over 2A
The formula for finding the angles is called " Pythagorean Thyrum " It states that a squred plus b squared equals c squared so therefore c squared minus a squared will equal b squared. i hope that helps
No, unless "a" happens to be equal to 0, or to 1.
All the time
he made the theorem C squared = A squared + B squared and A squared = C squared - B squared or B squared = C squared - A squared
Use (-b + or - sqrt(b^2-4ac))/(2a) A is 10 B is -9 C is -6
hello
the square root of b squared minus 4 times a times c
Using the quadratic formula-- ((negative b plus or minus the square root of b squared minus 4ac) divided by (2a)) you'll want to google that so you can see it in numerical form. a, b, and c are the coefficiants of your three terms ( 2 is a, -5 is b, and 2 is c) The answer is (x-2)(2x-1).
a - b = c -(a - b) = -c b - a = -c