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To factor the expression ( x^2 + 4x - 80 ), first look for two numbers that multiply to (-80) (the constant term) and add up to (4) (the coefficient of the linear term). The numbers (10) and (-8) fit this requirement. Thus, you can rewrite the expression as ( (x + 10)(x - 8) ). Therefore, the factored form of ( x^2 + 4x - 80 ) is ( (x + 10)(x - 8) ).
What else can I help you with?
What is a common factor of x2-16 and x2-4x?
x2 - 4
Factor 9 - x2?
9 - x2 will factor into (3 - x)(3 + x)
What is 4x80?
4 x 80 = 320
Does x2-14 factor?
x2-14 does factor but not pretty; it factors to: (x+sqrt14)(x-sqrt14).
How do you factor x2-3x-28?
x2-3x-28
How do you factor x2 6x-2?
x2 + 6x - 2 can not be factored
Factor x5 plus x2?
x^(5) + x^(2)= x^(2) ))x^(3) + 1) Think of '1' as '1^(3)' Hence x^(2)(x^(3) + 1^(3)) x^(2)(x + 1)(x^(2) - x + 1^(2)) or x^(2)(x + 1)(x^(2) - x + 1) Done!!!!!
How do you factor x2-9x?
x2-9x = x(x-9)
How do you factor x2-x?
x2-x=x(x-1)
How can you factor x2-13 plus 30?
x2 - 13 + 30 = x2 + 17, which has no real factors.
How do you factor x2 - 6x?
x2-6x can be factored into x(x-6). Simply factor out the "x" from both factors.
Which of the the following are the faction x3 plus 3x2?
If you mean "factors", the two monomials have the common factor x2. Divide each factor by x2 to get the other factor.
