To factor the expression ( x^2 + 4x - 80 ), first look for two numbers that multiply to (-80) (the constant term) and add up to (4) (the coefficient of the linear term). The numbers (10) and (-8) fit this requirement. Thus, you can rewrite the expression as ( (x + 10)(x - 8) ). Therefore, the factored form of ( x^2 + 4x - 80 ) is ( (x + 10)(x - 8) ).
x2 - 4
9 - x2 will factor into (3 - x)(3 + x)
4 x 80 = 320
x2-14 does factor but not pretty; it factors to: (x+sqrt14)(x-sqrt14).
x2-3x-28
x2 + 6x - 2 can not be factored
x2-9x = x(x-9)
x2-x=x(x-1)
x2 - 13 + 30 = x2 + 17, which has no real factors.
x2-6x can be factored into x(x-6). Simply factor out the "x" from both factors.
If you mean "factors", the two monomials have the common factor x2. Divide each factor by x2 to get the other factor.
You can't factor it