x3 - 3x2 + 4
Since the coefficients of the odd powers of x (=1) is the same as the sum of the even powers (-3+4=1), then x = -1 must be a root. That is to say, (x + 1) is a factor.
So you can rewrite the expression as
x3 + x2 - 4x2 - 4x + 4x + 4
= x2(x + 1) - 4(x + 1) + 4(x + 1)
= (x + 1)*(x2 - 4x + 4)
= (x + 1)*(x - 2)2
a2 - 4a + 4
(2x+4)(x+1)
(3x + 4)(3x + 4)
That's 44v + 4 which factors to 4(11v + 1)
(b + 4)(b + 4)
Not factorable
(2x + 1)(x + 4)
a2 - 4a + 4
(2x+4)(x+1)
(3x + 4)(3x + 4)
4(x + 1)(x + 1)
Oh, dude, you're hitting me with some math now? Alright, so you're looking at the quadratic expression x^2 + 5x + 4. To factor this, you want to find two numbers that multiply to 4 (the constant term) and add up to 5 (the coefficient of the x term). Those numbers are 1 and 4, so the factored form is (x + 1)(x + 4). That's it, easy peasy lemon squeezy!
(x-1)(x+4)
That's 44v + 4 which factors to 4(11v + 1)
x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)
x3 + 4x2 + x + 4 = (x + 4)(x2 + 1)
(b + 4)(b + 4)