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Factor x3 plus 2x2 plus 3x plus 6?
x3 + 2x2 + 3x + 6 = x2(x + 2) + 3(x + 2) = (x + 2)(x2 + 3)
How do you factor x3 plus 2x2 plus 4x plus 8?
(x + 2)(x^2+4)
Factor Completely x3 plus 8?
x3 + 8 = x3 + 23 = (x + 2)(x2 + 2x + 22) = (x + 2)(x2 + 2x + 4)
How to Solve this problem x-2 divide x3-2x2 plus x-3?
That depends on what the problem is. The expresion alone is not a problem. It's just an expression. Presumably, what you want to do here is to simplify it. We're given: (x - 2) / (x3 - 2x2 + x - 3) Let's start by tring to divide the numerator into the denominator using long division: x2 + 1 (x - 2) x3 - 2x2 + x - 3 x3 - 2x2 0 + x - 3 x - 2 -1 R Since we get a non-zero remainder, we can see that x - 2 is not a factor of the denominator. And in fact, looking further into it, we will find that the denominator can not be factored, and so this problem can not be simplified.
What is x3-2x2 plus 3x-6 factored out?
(x-2)(x^2+3)
