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Factor x3 plus 2x2 plus 3x plus 6?
x3 + 2x2 + 3x + 6 = x2(x + 2) + 3(x + 2) = (x + 2)(x2 + 3)
How do you factor x3 plus 2x2 plus 4x plus 8?
(x + 2)(x^2+4)
Factor Completely x3 plus 8?
x3 + 8 = x3 + 23 = (x + 2)(x2 + 2x + 22) = (x + 2)(x2 + 2x + 4)
How to Solve this problem x-2 divide x3-2x2 plus x-3?
That depends on what the problem is. The expresion alone is not a problem. It's just an expression. Presumably, what you want to do here is to simplify it. We're given: (x - 2) / (x3 - 2x2 + x - 3) Let's start by tring to divide the numerator into the denominator using long division: x2 + 1 (x - 2) x3 - 2x2 + x - 3 x3 - 2x2 0 + x - 3 x - 2 -1 R Since we get a non-zero remainder, we can see that x - 2 is not a factor of the denominator. And in fact, looking further into it, we will find that the denominator can not be factored, and so this problem can not be simplified.
What is x3-2x2 plus 3x-6 factored out?
(x-2)(x^2+3)
Factor the polynomial x3-2x2 plus x-2?
x3 - 2x2 + x - 2 =(x - 2)(x2 + 1)
What is the factor of X3 - 2x2 - 4x plus 8?
x3 - 2x2 - 4x + 8 = (x2 - 4)(x - 2) = (x + 2)(x - 2)(x - 2)
Factor x3 plus 2x2 plus 3x plus 6?
x3 + 2x2 + 3x + 6 = x2(x + 2) + 3(x + 2) = (x + 2)(x2 + 3)
How do you factor x3 plus 2x2 plus 4x plus 8?
(x + 2)(x^2+4)
Factor completaly x3 plus 2x3 plus 4xplus 8?
If that's 2x2, the answer is (x + 2)(x2 + 4)
Factor Completely x3 plus 8?
x3 + 8 = x3 + 23 = (x + 2)(x2 + 2x + 22) = (x + 2)(x2 + 2x + 4)
Factor completely x3-y3?
(x - y)(x^2 + xy + y^2
How do you factor. Px x4 - x3 2x2 - 4x - 8?
x^2(x + 2) - 1(x+2) (x+2)(x-1)(x+1)
Describe how the Factor Theorem can be used to determine whether x plus 1 is a factor of x3-2x2-8x-5?
The factor theorem states that for any polynomial function f(x), if f(a) = 0, then (x-a) is a factor of f(x). Let f(x) = x3-2x2-8x-5. If (x+1) is a factor, then f(-1) = 0. (x+1 = x - (-1)) Input x = -1 into f: (-1)3-2(-1)2-8(-1)-5 f(-1) = -1 -2 + 8 - 5 f(-1) = 0. Since f(-1) = 0, (x+1) is a factor of x3-2x2-8x-5. Q.E.D.
How to Solve this problem x-2 divide x3-2x2 plus x-3?
That depends on what the problem is. The expresion alone is not a problem. It's just an expression. Presumably, what you want to do here is to simplify it. We're given: (x - 2) / (x3 - 2x2 + x - 3) Let's start by tring to divide the numerator into the denominator using long division: x2 + 1 (x - 2) x3 - 2x2 + x - 3 x3 - 2x2 0 + x - 3 x - 2 -1 R Since we get a non-zero remainder, we can see that x - 2 is not a factor of the denominator. And in fact, looking further into it, we will find that the denominator can not be factored, and so this problem can not be simplified.
X3 plus 6x2 - 4x - 24 factor completely?
x3 + 6x2 - 4x - 24 = (x + 6)(x2 - 4) = (x + 6)(x + 2)(x - 2)
What is x3-2x2 plus 3x-6 factored out?
(x-2)(x^2+3)
