x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)
x3 - 2x2 + x - 2 =(x - 2)(x2 + 1)
x3 + 2x2 + 5x + 4 = (x + 1)(x2 + x + 4)
x3 + 2x2 - 19x - 20 = x3 + x2 + x2 + x - 20x - 20 = x2(x + 1) - x(x + 1) - 20(x + 1) = (x + 1)(x2 + x - 20) = (x + 1)(x - 4)(x + 5)
Dividend: 4x4-x3+17x2+11x+4 Divisor: 4x+3 Quotient: x3-x2+5x-1 Remainder: 7
(x + 2)(x^2+4)
(x3 + 3x2 - 2x + 7)/(x + 1) = x2 + 2x - 4 + 11/(x + 1)(multiply x + 1 by x2, and subtract the product from the dividend)1. x2(x + 1) = x3 + x22. (x3 + 3x2 - 2x + 7) - (x3 + x2) = x3 + 3x2 - 2x + 7 - x3 - x2 = 2x2 - 2x + 7(multiply x + 1 by 2x, and subtract the product from 2x2 - 2x + 7)1. 2x(x + 1) = 2x2 + 2x2. (2x2 - 2x + 7) - (2x2 + 2x) = 2x2 - 2x + 7 - 2x2 - 2x = -4x + 7(multiply x + 1 by -4, and subtract the product from -4x + 7)1. -4(x + 1) = -4x - 42. -4x + 7 - (-4x - 4) = -4x + 7 + 4x + 4 = 11(remainder)
x3 + x2 + 4x + 4 = (x2 + 4)(x + 1)
x3 - 2x2 + x - 2 =(x - 2)(x2 + 1)
x3 + 2x2 + 3x + 6 = x2(x + 2) + 3(x + 2) = (x + 2)(x2 + 3)
If that's 2x2, the answer is (x + 2)(x2 + 4)
x3 + 2x2 + 5x + 4 = (x + 1)(x2 + x + 4)
x3 + 2x2 - 35x = x(x + 7)(x - 5)
x3 + 6x2 - 4x - 24 = (x + 6)(x2 - 4) = (x + 6)(x + 2)(x - 2)
64 is the cube of 4 so: x3 + 64 = (x + 4)(x2 - 4x + 16)
x3 + 2x2 - 8x + 5 = 0 x(2x - 8) + 5 = 0
Differentiate the function with respect to x: d/dx (x3 - 2x2 - 5x + 6) = 3x2 - 4x - 5 Set this derivative = 0 and solve. 3x2 - 4x - 5 = 0 implies that x = -0.7863 or 2.1196 (to 4 dp)