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Earn +20 ptsQ: How do you factor x3 plus 2x2 plus 4x plus 8?
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When x3 plus 3x2-2x plus 7 is divided by x plus 1 what is the remainder?
(x3 + 3x2 - 2x + 7)/(x + 1) = x2 + 2x - 4 + 11/(x + 1)(multiply x + 1 by x2, and subtract the product from the dividend)1. x2(x + 1) = x3 + x22. (x3 + 3x2 - 2x + 7) - (x3 + x2) = x3 + 3x2 - 2x + 7 - x3 - x2 = 2x2 - 2x + 7(multiply x + 1 by 2x, and subtract the product from 2x2 - 2x + 7)1. 2x(x + 1) = 2x2 + 2x2. (2x2 - 2x + 7) - (2x2 + 2x) = 2x2 - 2x + 7 - 2x2 - 2x = -4x + 7(multiply x + 1 by -4, and subtract the product from -4x + 7)1. -4(x + 1) = -4x - 42. -4x + 7 - (-4x - 4) = -4x + 7 + 4x + 4 = 11(remainder)
Factor x3 plus 2x2 plus 3x plus 6?
x3 + 2x2 + 3x + 6 = x2(x + 2) + 3(x + 2) = (x + 2)(x2 + 3)
What is the factorization of x3 plus 2x2 35x?
x3 + 2x2 - 35x = x(x + 7)(x - 5)
Factor x3 plus 64?
64 is the cube of 4 so: x3 + 64 = (x + 4)(x2 - 4x + 16)
How do you factorise x3 plus 2x2-8x plus 5 equals 0?
x3 + 2x2 - 8x + 5 = 0 x(2x - 8) + 5 = 0
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