x8-1 becomes (x4 + 1) (x4 - 1) - perfect square and then (x4 + 1) (x2 - 1)(x2 + 1) - perfect square again. and then (x4 + 1)(x2 + 1)(x + 1)(x - 1) - perfect square again
-32
x4 + 7x2 - 60 = x4 + 12x2 - 5x2 - 60 = x2(x2 + 12) - 5(x2 +12) = (x2 - 5)(x2 +12)
A power can be factored in many different ways; for example: x5 = x times x4 = x2 times x3. When such a power appears as a term in combination with other expressions, you should look out for common factoring patterns. Here are two examples: x2 + x5 Here, you can use the pattern "common factor". In this case, both parts have the common factor x2, so you can factor it out. x4 - 1 Here, you can use the pattern "difference of squares". Note that x4 is the square of x2, and 1 is the square of 1.
If there is a remainder then it's not a factor otherwise yes
(x4 - 3)(x4 + 3)
x times x times x times x = x4
Greatest common factor of x4 and x3 is x3.
0,6x4=15x3
It is: 1(x4+4y8) and can't be factored any further
The answer to this question is x4 easy right?!
-x2(x + 10)(x - 10)
It can be factored to: 4(x-1)
1 - x4 = (1 - x2)(1 + x2) = (1 - x)(1 + x)(1 + x2) (difference of squares)
(x^2 - 3)(x^2 + 3)
(x2 - 3)(x2 + 3)(x4 + 9)
(x - 1)(x + 1)(x2 + 1)