That doesn't factor neatly. Applying the quadratic formula, we find two real solutions: (1 plus or minus the square root of 13) divided by 2
x = 2.3027756377319946
x = -1.3027756377319946
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x(x4+x3+x2+x+1)
x3 + 4x2 - 16x - 64 = (x + 4)(x + 4)(x - 4).
x cubed, or x^3 x(x2)= x3
Answer: x (x2-x)
x3 - 4x2 + x + 6 The sum of the odd coefficients equals the sum of the even coefficients, so (x + 1) is a factor. So x3 - 4x2 + x + 6 = x3 + x2 - 5x2 - 5x + 6x + 6 = x2(x + 1) - 5x(x + 1) + 6(x + 1) = (x + 1)(x2 - 5x + 6) = (x + 1)(x - 2)(x - 3)