This equation (where the above expression equals 0) has imaginary roots and so will need to be solved using the quadratic formula and the use of the imaginary number i.
(3r - 2)(3r - 2) or (3r - 2) squared.
(x + 3)(3x - 2)
2(5x - 1)(3x - 2)
it is (x-y)(x-y) :)
(x - 2)(2x + 7)
(a - 2)(a^2 + 6)
(3r - 2)(3r - 2) or (3r - 2) squared.
Factor out -2: -2(x squared +11x-20). This is fully factored.
(x + 3)(3x - 2)
2(5x - 1)(3x - 2)
it is (x-y)(x-y) :)
(2x - 3)(x + 2)
(x-1)(x+2)
(x - 2)(2x + 7)
(2y - 5)(y - 2)
(y - 2)(y - 7)
(5x - 2)(x - 5)