dont know sorry
7x - 12y = any other number.
y(3y^2 - 12y + 4)
It is: 3(5x-4y)
Pull out the common factor of 2 ... 2(y^2+6y-16) Then just factor (y^2+6y-16) ... (y-2)(y+8)
I assume the expression is y2+12y+27 as I cannot see the operation symbols between them (editor problem?). If you agree with this then y2 + 12y + 27 = y2 + 9y + 3y + 27 = y(y + 9) + 3(y + 9) = (y + 3)(y + 9)
y2 + 12y + 5y + 60 y (y + 12) + 5 (y + 12) (y + 12 )(y + 5)
factor 4y - 32
12Y + 9 all I can see to factor out is 3 3(4Y + 3)
dont know sorry
7x - 12y = any other number.
y(3y^2 - 12y + 4)
It is: y2
It is: 3(5x-4y)
Pull out the common factor of 2 ... 2(y^2+6y-16) Then just factor (y^2+6y-16) ... (y-2)(y+8)
Oh, dude, it's like you just gotta pull out the common factor, which in this case is 4. So, you're left with 4(x + 3y). And that's it, like, you're done. Easy peasy lemon squeezy.
The GCF is 6y